TS EAMCET · Physics · Mechanical Properties of Fluids

A copper wire of cross-sectional area $0.01 {cm}^{2}$ is under a tension of $22 N$ . Find the percentage change in the cross-sectional area (Young's modulus of copper $= 1.1 \times 10^{11} N m^{- 2}$ and Poisson ratio $= 0.32$ )

A $12.8 \times 10^{- 3}$
B $8.6 \times 10^{- 3}$
C $6.4 \times 10^{- 3}$
D $2.8 \times 10^{- 3}$

Verified Solution

Answer & Solution

Correct Answer

(A) $12.8 \times 10^{- 3}$

Step-by-step Solution

Detailed explanation

Given, The area of cross-section of copper wire is A=0.01 cm2 Tension in the wire is T=22 N Young's modulus of copper wire is Y=1.1×1011 N m-2 Poisson ratio is σ=0.32 Using the formula of Young's modulus of wire, Y=FA×ldl The longitudinal…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From TS EAMCET

Explore more questions on app

A copper wire of cross-sectional area 0.01 cm2 is under a tension of 22 N. Find the percentage change in the cross-sectional area (Young's modulus of copper =1.1×1011 N m-2 and Poisson ratio =0.32 )

Step-by-step Solution

A copper wire of cross-sectional area $0.01 {cm}^{2}$ is under a tension of $22 N$ . Find the percentage change in the cross-sectional area (Young's modulus of copper $= 1.1 \times 10^{11} N m^{- 2}$ and Poisson ratio $= 0.32$ )