TS EAMCET · Physics · Current Electricity
A conducting wire of cross-sectional area \(1 \mathrm{~cm}^2\) has \(3 \times 10^{23}\) charge carriers per \(\mathrm{m}^3\). If wire carries a current of \(24 \mathrm{~mA}\), then drift velocity of carriers is
- A \(5 \times 10^{-2} \mathrm{~m} / \mathrm{s}\)
- B \(0.5 \mathrm{~m} / \mathrm{s}\)
- C \(5 \times 10^{-3} \mathrm{~m} / \mathrm{s}\)
- D \(5 \times 10^{-6} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(5 \times 10^{-3} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Given, cross-sectional area, \(A=1 \mathrm{~cm}^2=10^{-4} \mathrm{~m}^2\) Charge density, \(n=3 \times 10^{23} \mathrm{~m}^{-3}\) Current through wire, \(I=24 \times 10^{-3}\) A We know that, for conductors, \(I=n A e v_d\)…
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