TS EAMCET · Physics · Alternating Current
A \(L-C-R\) series circuit is connected to a source of alternating current. At resonance, the applied voltage and the current flowing through the circuit will have a phase difference of
- A \(\pi\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{4}\)
- D \(0^{\circ}\)
Answer & Solution
Correct Answer
(D) \(0^{\circ}\)
Step-by-step Solution
Detailed explanation
In \(L-C-R\) series circuit, phase difference \(\phi\) between current and voltage is related as, \(\cos \phi=\frac{R}{Z}\)....(i) At resonance condition, \(X_L=X_C\) \(\therefore Z=\sqrt{R^2+\left(X_L-X_C\right)^2}=\sqrt{R^2+0}=R\) \(\therefore\) from Eqs. (i),…
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