TS EAMCET · Physics · Rotational Motion
If the moment of inertia of a uniform solid cylinder about the axis of the cylinder is \(\frac{1}{n}\) times its moment of inertia about an axis passing through its midpoint and perpendicular to its length, then the ratio of the length and radius of the cylinder is
- A \(\sqrt{2(3 n+1)}\)
- B \(\sqrt{2(3 n-1)}\)
- C \(\sqrt{3(2 n+1)}\)
- D \(\sqrt{3(2 n-1)}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{3(2 n-1)}\)
Step-by-step Solution
Detailed explanation
\(I_{axis} = \frac{1}{2} M R^2\) \(I_{\perp} = \frac{1}{4} M R^2 + \frac{1}{12} M L^2\) \(\frac{1}{2} M R^2 = \frac{1}{n} \left( \frac{1}{4} M R^2 + \frac{1}{12} M L^2 \right)\) \(\frac{n}{2} R^2 = \frac{1}{4} R^2 + \frac{1}{12} L^2\)…
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