TS EAMCET · Physics · Mechanical Properties of Solids
A steel wire of length 3 m and a copper wire of length 2.2 m are connected end to end. When the combination is stretched by a force, the net elongation is 1.05 mm . If the area of cross-section of each wire is \(6 \mathrm{~mm}^2\), then the load applied is (Young's module of steel and copper are respectively \(2 \times 10^{11} \mathrm{Nm}^{-2}\) and \(1.1 \times 10^{11} \mathrm{Nm}^{-2}\) )
- A 180 N
- B 90 N
- C 135 N
- D 120 N
Answer & Solution
Correct Answer
(A) 180 N
Step-by-step Solution
Detailed explanation
Young's modulus, \(\mathrm{Y}=\frac{\mathrm{F}}{\mathrm{A}} \left\lvert\, \frac{\Delta \mathrm{l}}{\mathrm{I}_{\mathrm{o}}} \Rightarrow \Delta \mathrm{l}=\frac{\mathrm{F}}{\mathrm{Y}_{\mathrm{A}}} \mathrm{l}_{\mathrm{o}}\right.\)…
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