TS EAMCET · Physics · Current Electricity
A cylindrical wire \(P\) has resistance \(10 \Omega\). A second wire \(Q\) has length and diameter half that of \(P\). If the material of both the wires is same, then resistance of wire \(Q\) is
- A \(10 \Omega\)
- B \(20 \Omega\)
- C \(5 \Omega\)
- D \(\frac{5}{2} \Omega\)
Answer & Solution
Correct Answer
(B) \(20 \Omega\)
Step-by-step Solution
Detailed explanation
Given, length of wire, \(P=l\) Length of wire, \(Q=\frac{l}{2}\) Diameter of wire, \(P=d\) Diameter of wire, \(Q=\frac{d}{2}\) Resistance \(R=\rho \cdot \frac{l}{A}=\rho \cdot \frac{l}{\pi d^2 / 4}\)…
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