TS EAMCET · Physics · Wave Optics
In Young's double slit experiment, an interference pattern is obtained on a screen by a light of wavelength \(6000 Å\) coming from the coherent sources \(S_1\) and \(S_2\). At certain point \(P\) on the screen third dark fringe is formed. Then, the path difference \(S_1 P-S_2 P\) in microns is:
- A 0.75
- B 1.5
- C 3
- D 4.5
Answer & Solution
Correct Answer
(B) 1.5
Step-by-step Solution
Detailed explanation
\(\lambda=6000 Å=6 \times 10^{-7} \mathrm{~m}\) Path difference for dark fringe; \(\Delta x=(2 n+1) \lambda / 2\) For third dark fringe, \(n=2\) \(\therefore \quad \Delta x=(2 \times 2+1) \times \frac{6 \times 10^{-7}}{2}\) \(=\frac{5 \times 6 \times 10^{-7}}{2}\)…
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