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TS EAMCET · Physics · Motion In One Dimension

At time \(t=0\), a particle leaves the origin and moves in the positive direction of the \(X\)-axis. If the velocity of the particles varies as \(\mathbf{v}(t)=\mathbf{v}_0\left(1-\frac{t}{t_0}\right),\left|\mathbf{v}_0\right|=10 \mathrm{~m} / \mathrm{s}\) and \(t_0=10 \mathrm{~s}\), then the distance covered by the particle during the first \(20 \mathrm{~s}\) is

  1. A 200 m
  2. B 100 m
  3. C 0 m
  4. D 400 m
Verified Solution

Answer & Solution

Correct Answer

(B) 100 m

Step-by-step Solution

Detailed explanation

Given that, At \(t=0, x=0\) and \(u=\mathbf{v}=-\mathbf{v}_0\) At any time \(t\), velocity of particle, \[ \mathbf{v}=\mathbf{v}_0\left(1-\frac{t}{t_0}\right)=\mathbf{v}_0-\frac{\mathbf{v}_0}{t_0} t \] Velocity will become zero at time \(t_1\)…
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