TS EAMCET · Physics · Capacitance
The time in seconds required to produce a potential difference of \(20 \mathrm{~V}\) across a capacitor of \(1000 \mu \mathrm{F}\) when it is charged at the steady rate of \(200 \mu \mathrm{C} / \mathrm{s}\) is
- A \(50\)
- B \(100\)
- C \(150\)
- D \(200\)
Answer & Solution
Correct Answer
(B) \(100\)
Step-by-step Solution
Detailed explanation
Total charge \[ \begin{aligned} & =1000 \times 10^{-6} \times 20 \\ & =20,000 \mu \mathrm{C} \end{aligned} \] \[ \text { Rate of charge }=200 \mu \mathrm{C} / \mathrm{s} \] \[ \therefore \text { Time taken }=\frac{20,000}{200}=100 \mathrm{sec} \]
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