TS EAMCET · Physics · Thermodynamics
The ratio of the work done, change in internal energy and heat absorbed when a diatomic gas expands at constant pressure is
- A \(2: 3: 5\)
- B \(7: 5: 2\)
- C \(5: 3: 2\)
- D \(2: 5: 7\)
Answer & Solution
Correct Answer
(D) \(2: 5: 7\)
Step-by-step Solution
Detailed explanation
\(W = nR\Delta T\) \(\Delta U = nC_v\Delta T = n\left(\frac{5}{2}R\right)\Delta T\) \(Q = nC_p\Delta T = n\left(\frac{7}{2}R\right)\Delta T\) \(W : \Delta U : Q = nR\Delta T : \frac{5}{2}nR\Delta T : \frac{7}{2}nR\Delta T\)…
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