TS EAMCET · Physics · Thermal Properties of Matter
A container is filled with a liquid that cools from \(100{ }^{\circ} \mathrm{C}\) to \(70^{\circ} \mathrm{C}\) in \(5 \mathrm{~min}\), when kept at room temperature of \(30^{\circ} \mathrm{C}\). The time that it must have taken to cool down to \(80^{\circ} \mathrm{C}\) from its initial temperature approximately is
- A \(1.7 \mathrm{~min}\)
- B \(2.6 \mathrm{~min}\)
- C \(8.2 \mathrm{~min}\)
- D \(4.1 \mathrm{~min}\)
Answer & Solution
Correct Answer
(B) \(2.6 \mathrm{~min}\)
Step-by-step Solution
Detailed explanation
Given that, In first case, \[ \begin{array}{c|c} \mathrm{T}_1=100^{\circ} \mathrm{C} & \mathrm{T}_0=30^{\circ} \mathrm{C} \\ \mathrm{T}_2=70^{\circ} \mathrm{C} & \text { time, } t_1=5 \mathrm{~min}=300 \mathrm{~s} \end{array} \] According to Newton's law of cooling,…
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