TS EAMCET · Physics · Mechanical Properties of Fluids
The work done in blowing a soap bubble of volume \(V\) is \(W\). The work done in blowing the bubble of volume \(2 V\) from the same soap solution is
- A \(\frac{W}{2}\)
- B \(\sqrt{2} \mathrm{~W}\)
- C \((2)^{1 / 3} W\)
- D \((4)^{1 / 3} W\)
Answer & Solution
Correct Answer
(D) \((4)^{1 / 3} W\)
Step-by-step Solution
Detailed explanation
Work done in blowing a soap bubble, \(\mathrm{W}=\mathrm{T} \cdot \mathrm{A}=\mathrm{T}\left(4 \pi \mathrm{r}^2\right), \mathrm{W} \propto \mathrm{r}^2\) Also, Volume, \(V=\frac{4}{3} \pi \mathrm{r}^3 \Rightarrow \mathrm{r} \propto \mathrm{V}^{1 / 3}\)…
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