TS EAMCET · Physics · Waves and Sound
An air column in a tube \(32 \mathrm{~cm}\) long, closed at one end, is in resonance with a tuning fork. The air column in another tube, open at both ends, of length \(66 \mathrm{~cm}\) is in resonance with another tuning fork. When these two tuning forks are sounded together, they produce 8 beats per second. Then the frequencies of the two tuning forks are, (Consider fundamental frequencies only)
- A \(250 \mathrm{~Hz}, 258 \mathrm{~Hz}\)
- B \(240 \mathrm{~Hz}, 248 \mathrm{~Hz}\)
- C \(264 \mathrm{~Hz}, 256 \mathrm{~Hz}\)
- D \(280 \mathrm{~Hz}, 272 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(C) \(264 \mathrm{~Hz}, 256 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
We knows frequency of a closed end an column \[ n_1=\frac{v}{4 / 1} \] We knows frequency of a open end an column \[ n_2=\frac{v}{2 l_2} \] Given, \(l_1=32 \mathrm{~cm}, I_2=66 \mathrm{~cm}\) and \(\quad n_1-n_2=8\) heat \(/ \mathrm{s}\) So,…
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