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TS EAMCET · Physics · Work Power Energy

A force acts on a \(30 \mathrm{~g}\) particle in such a way that the position of the particle as a function of time is given by \(x=\alpha t^2\), where \(x\) is in metre, \(t\) is in seconds and \(\alpha=1 \mathrm{~m} / \mathrm{s}^2\). The work done during the first \(4 \mathrm{~s}\) is

  1. A 0.96 J
  2. B 0.45 J
  3. C 0.49 J
  4. D 0.53 J
Verified Solution

Answer & Solution

Correct Answer

(A) 0.96 J

Step-by-step Solution

Detailed explanation

Given, mass of particle, \(m=30 \mathrm{~g}=3 \times 10^{-2} \mathrm{~kg}\) Displacement of the particle is given as \(x=\alpha t^2\) \(\therefore\) Velocity, \(v=\frac{d x}{d t}=\frac{d}{d t} \alpha t^2 \Rightarrow v=2 \alpha t\) Acceleration,…