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TS EAMCET · Physics · Magnetic Effects of Current

A current I=5Aflows along a thin wire shaped as shown in figure. The radius of curved part of the wire is equal to R=100mm, the angle 2ϕ=90°. The magnitude of magnetic field at the point Ois approximately
Use,μ04π=10-7TmA-1

  1. A 33.6 μT
  2. B 38.4 μT
  3. C 48.7 μT
  4. D 25.2 μT
Verified Solution

Answer & Solution

Correct Answer

(A) 33.6 μT

Step-by-step Solution

Detailed explanation

Magnetic field due to curved part=μ0I4πR2π-2ϕ-k^=10-7×50.1×2π-π2-k^≈23.6μT-k^ Magnetic field due to straight part=μ0I4πdsinϕ1+sinϕ2-k^=μ0I4πrcos45°sin45°+sin45°-k^=10-7×50.1×12×12+12-k^=10μT-k^Therefore, net magnetic fieldB→net=33.6μT-k^
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