TS EAMCET · Physics · Motion In Two Dimensions
The equations of motion of a projectile are given by \(x=36 t\) metre and \(2 y=96 t-9.8 t^2\) metre. The angle of projection is :
- A \(\sin ^{-1}\left(\frac{4}{5}\right)\)
- B \(\sin ^{-1}\left(\frac{3}{5}\right)\)
- C \(\sin ^{-1}\left(\frac{4}{3}\right)\)
- D \(\sin ^{-1}\left(\frac{3}{4}\right)\)
Answer & Solution
Correct Answer
(A) \(\sin ^{-1}\left(\frac{4}{5}\right)\)
Step-by-step Solution
Detailed explanation
\(x=36 t\) metre \(2 y=\left(96 t-9.8 t^2\right)\) metre Standard equations are, \(x=(u \cos \theta) t\) \(y=u \sin \theta t-\frac{1}{2} g t^2\) \(u \cos =36\) \(u \sin \theta=\frac{96}{2}=48\)…
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