TS EAMCET · Physics · Work Power Energy
A bucket filled with water is tied to a rope of length \(0.5 \mathrm{~m}\) and is rotated in a circular path in vertical plane. The least velocity it should have at the lowest point of circle so that water does not spill is, \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
- A \(\sqrt{5} \mathrm{~m} / \mathrm{s}\)
- B \(\sqrt{10} \mathrm{~m} / \mathrm{s}\)
- C \(5 \mathrm{~m} / \mathrm{s}\)
- D \(2 \sqrt{5} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(5 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
For water not to spill out of the bucket, \(\begin{aligned} v_{\min } & =\sqrt{5 g R} \\ & =\sqrt{5 \times 10 \times 0.5} \\ & =5 \mathrm{~m} / \mathrm{s}\end{aligned}\)
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