TS EAMCET · Physics · Dual Nature of Matter
A charged particle is accelerated from rest through a certain potential difference. The de-Broglie wavelength is \(\lambda_1\) when it is accelerated through \(V_1\) and is \(\lambda_2\) when accelerated through \(V_2\). The ratio \(\lambda_1 / \lambda_2\) is
- A \(V_1^{3 / 2}: V_2^{3 / 2}\)
- B \(V_2^{1 / 2}: V_1^{1 / 2}\)
- C \(V_1^{1 / 2}: V_2^{1 / 2}\)
- D \(V_1^2: V_2^2\)
Answer & Solution
Correct Answer
(B) \(V_2^{1 / 2}: V_1^{1 / 2}\)
Step-by-step Solution
Detailed explanation
The de-Broglie wavelength associated with a charged particle is given by \[ \lambda=\frac{h}{\sqrt{m q V}} \] where, \(h=\) planck's constant \(m=\) mass of charged particle \(q=\) charge on the particle \(V=\) potential at which the charged particle is accelerated.…
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