TS EAMCET · Physics · Alternating Current
A capacitor \(50 \mu \mathrm{F}\) is connected to a power source \(V=220 \sin 50 t\) ( \(V\) in volt, \(t\) in second). The value of rms current (in ampere)
- A \(\frac{\sqrt{2}}{0.55} \mathrm{~A}\)
- B \(0.55 \mathrm{~A}\)
- C \(\sqrt{2} \mathrm{~A}\)
- D \(\frac{(0.55)}{\sqrt{2}} \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(\frac{(0.55)}{\sqrt{2}} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
The given \[ \begin{aligned} & C=50 \mu \mathrm{F}=50 \times 10^{-6} \mathrm{~F} \\ & V=220 \sin 50 t \end{aligned} \] But we know that \[ V=V_0 \sin \omega t \] Comparing both equations \[ V_0=220 \mathrm{~V}, \omega=50 \mathrm{rad} / \mathrm{s} \] The capacitive reactance of…
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