TS EAMCET · Physics · Rotational Motion
The moment of inertia of a meter scale of mass \(0.6 \mathrm{~kg}\) about an axis perpendicular to the scale and located at the \(20 \mathrm{~cm}\) position on the scale in \(\mathrm{kg}-\mathrm{m}^2\) is : (Breadth of the scale is negligible)
- A 0.078
- B 0.104
- C 0.148
- D 0.208
Answer & Solution
Correct Answer
(A) 0.078
Step-by-step Solution
Detailed explanation
\(m=0.6 \mathrm{~kg}\) Mass per unit length \(=\frac{0.6}{100} \mathrm{~kg} / \mathrm{cm}\) Mass of part \(A B, m_1=\frac{0.6}{100} \times 20=\frac{0.6}{5} \mathrm{~kg}\) Mass of part \(B C, m_2=\frac{0.6}{100} \times 80=\frac{0.6 \times 4}{5}=\frac{2.4}{5} \mathrm{~kg}\) Moment…
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