TS EAMCET · Physics · Ray Optics
Two lenses \(A\) and \(B\) having focal lengths \(2.0 \mathrm{~cm}\) and \(5.0 \mathrm{~cm}\), respectively are placed \(14 \mathrm{~cm}\) apart. Lens \(A\) is placed to the left of lens \(B\). An object is placed \(3 \mathrm{~cm}\) to the left of lens \(A\). The distance of the image from lens \(A\) will be
- A \(\frac{40}{3} \mathrm{~cm}\)
- B \(\frac{82}{3} \mathrm{~cm}\)
- C \(\frac{112}{5} \mathrm{~cm}\)
- D \(\frac{92}{5} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(\frac{82}{3} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Focal length of lens \(A, f_1=2 \mathrm{~cm}\), focal length lens \(B_1, f_2=5 \mathrm{~cm}\) The given situation is shown is the figure. For lens \(A\), \( u_1=-3 \mathrm{~cm}, v_1=? \) From lens formula, \(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)…
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