TS EAMCET · Physics · Motion In One Dimension
Consider that a truck is moving initially with \(54 \mathrm{~km} / \mathrm{h}\). It has stopped by the driver after looking at an obstacle with a deceleration of \(10 \mathrm{~m} / \mathrm{s}^2\). The distance travelled by truck before coming to rest is
- A \(12 \mathrm{~m}\)
- B \(11.25 \mathrm{~m}\)
- C \(11.30 \mathrm{~m}\)
- D \(11.20 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(11.25 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, initial velocity of truck, \(u=54 \mathrm{~km} / \mathrm{h}\) \(=54 \times \frac{5}{18}=15 \mathrm{~m} / \mathrm{s}\) Final velocity, \(v=0\) Deceleration, \(a=-10 \mathrm{~m} / \mathrm{s}^2\) As we know that, \(v^2=u^2+2 a s\)…
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