TS EAMCET · Physics · Capacitance
A metal plate of thickness \(2 \mathrm{~mm}\) and area \(36 \pi \mathrm{mm}^2\) - is slide in to a parallel plate capacitor of plate spacing \(6 \mathrm{~mm}\) and area \(36 \pi \mathrm{cm}^2\). The metal plate is at a distance \(3 \mathrm{~mm}\) from one of the plates. What is the capacitance of this arrangement? (Let \(\frac{\mathrm{I}}{4 \pi \mathrm{E}_0}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\) )
- A \(8 \mathrm{pF}\)
- B \(15 \mathrm{pF}\)
- C \(25 \mathrm{pF}\)
- D \(20 \mathrm{pF}\)
Answer & Solution
Correct Answer
(C) \(25 \mathrm{pF}\)
Step-by-step Solution
Detailed explanation
When metal plate of thickness \(2 \mathrm{~mm}\) is inserted into a parallel plate capacitor, then the arrangement is shown as, Given, thickness of plate, \(t=2 \mathrm{~mm}\) and area, \(A=36 \pi \mathrm{cm}^2\) The above circuit can be redrawn as, where,…
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