TS EAMCET · Physics · Ray Optics
The refractive index of a material of a planoconcave lens is \(5 / 3\), the radius of curvature is \(0.3 \mathrm{~m}\). The focal length of the lens in air is
- A \(-0.45 \mathrm{~m}\)
- B \(-0.6 \mathrm{~m}\)
- C \(-0.75 \mathrm{~m}\)
- D \(-1.0 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(-0.45 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Lens maker's formula \[ \frac{1}{f}=(\mu-1)\left[\frac{1}{R_1}-\frac{1}{R_2}\right] \] where, \(R_2=\infty, R_1=0.3 \mathrm{~m}\)…
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