TS EAMCET · Physics · Magnetic Effects of Current
A particle of mass \(m\) and charge \(q\) is moving in a cyclotron with magnetic field \(B\). The frequency of the circular motion of the particle is proportional to
- A \(\frac{q B}{m}\)
- B \(\frac{2 m}{q B}\)
- C \(\frac{m B}{q}\)
- D \(\frac{m q}{B}\)
Answer & Solution
Correct Answer
(A) \(\frac{q B}{m}\)
Step-by-step Solution
Detailed explanation
Frequency of rotation of a charged particle in a cyclotron is \(f=\frac{B q}{2 \pi m} \Rightarrow f \propto \frac{B q}{m}\)
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