ExamBro
ExamBro
TS EAMCET · Physics · Motion In Two Dimensions

A cannon placed on a cliff at a height of 375 m fires a cannon ball with a velocity of \(100 \mathrm{~ms}^{-1}\) at an angle of \(30^{\circ}\) above the horizontal. The horizontal distance between the cannon and the target is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

  1. A \(750 \sqrt{3} \mathrm{~m}\)
  2. B \(500 \sqrt{3} \mathrm{~m}\)
  3. C \(250 \sqrt{3} \mathrm{~m}\)
  4. D 750 m
Verified Solution

Answer & Solution

Correct Answer

(A) \(750 \sqrt{3} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Here vertical component of velocity \(u=-100 \sin 30^{\circ}\) \(=-50 \mathrm{~m} / \mathrm{s}\) Let \(t\) be the time taken to reach…
From TS EAMCET
Explore more questions on app