TS EAMCET · Physics · Dual Nature of Matter
The work function of the nickel is \(5 \mathrm{eV}\). When a light of wavelength \(2000 Å\) falls on it, it emits photoelectrons in the circuit. Then the potential difference necessary to stop the fastest electrons emitted is (given \(\left.h=6.67 \times 10^{-34} \mathrm{~J}-\mathrm{s}\right)\)
- A \(1.0 \mathrm{~V}\)
- B \(1.75 \mathrm{~V}\)
- C \(1.25 \mathrm{~V}\)
- D \(0.75 \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) \(1.25 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Stopping potential is given by \(\begin{aligned} e V_0 & =\frac{h c}{\lambda}-\phi \\ \therefore \quad e V_0 & =\frac{6.67 \times 10^{-34} \times 3 \times 10^8}{2 \times 10^{-7}}\end{aligned}\) \(-5 \times 1.6 \times 10^{-19}\)…
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