TS EAMCET · Physics · Center of Mass Momentum and Collision
A body of mass \(3 \mathrm{~kg}\) moving with a velocity \((2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\) collides with another body of mass \(4 \mathrm{~kg}\) moving with a velocity \([3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}] \mathrm{m} / \mathrm{s}\). The two bodies stick together after collision. The velocity of the composite body is
- A \(\frac{1}{7}(4 \hat{\mathbf{i}}+6 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})\)
- B \(\frac{1}{7}(18 \hat{\mathbf{i}}+17 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})\)
- C \(\frac{1}{7}(6 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}-6 \hat{\mathbf{k}})\)
- D \(1(9 \hat{\mathrm{i}}+8 \hat{\mathrm{i}}-6 \hat{\mathrm{k}})\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{7}(18 \hat{\mathbf{i}}+17 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})\)
Step-by-step Solution
Detailed explanation
Given, mass of first body \(\left(m_1\right)=3 \mathrm{~kg}\)…
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