TS EAMCET · Physics · Motion In One Dimension
The ratio of times taken by a freely falling body to travel first 5 m, second 5 m, third 5 m distances is
- A \(1: \sqrt{2}: \sqrt{3}\)
- B \(1: \sqrt{2-1}: \sqrt{3-2}\)
- C \(1: \sqrt{3}: \sqrt{5}\)
- D \(1: \sqrt{2}-1: \sqrt{3}-\sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(1: \sqrt{2}-1: \sqrt{3}-\sqrt{2}\)
Step-by-step Solution
Detailed explanation
\(t = \sqrt{\frac{2h}{g}}\) \(t_1 = \sqrt{\frac{2(5)}{g}}\) \(t_2 = \sqrt{\frac{2(10)}{g}} - \sqrt{\frac{2(5)}{g}}\) \(t_3 = \sqrt{\frac{2(15)}{g}} - \sqrt{\frac{2(10)}{g}}\) \(t_1 : t_2 : t_3 = \sqrt{5} : (\sqrt{10} - \sqrt{5}) : (\sqrt{15} - \sqrt{10})\)…
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