TS EAMCET · Physics · Ray Optics
If a ray of light passes through an equilateral prism such that the angle of incidence and the angle of emergence are both equal to \(70 \%\) of the angle of the prism, then the angle of minimum deviation is
- A \(36^{\circ}\)
- B \(18^{\circ}\)
- C \(42^{\circ}\)
- D \(24^{\circ}\)
Answer & Solution
Correct Answer
(D) \(24^{\circ}\)
Step-by-step Solution
Detailed explanation
using \(A+\delta=\mathbf{i}+e \Rightarrow \delta=\mathrm{i}+\mathrm{e}-\mathrm{A}\) Equilateral prism so \(\mathrm{A}=60^{\circ}\) And \(\mathrm{i}=\mathrm{e}=60^{\circ} \times \frac{70}{100}=42^{\circ}\) \(\therefore \delta=42^{\circ}+42^{\circ}-60^{\circ}=24^{\circ}\)
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