TS EAMCET · Physics · Work Power Energy
An elastic spring of wnstretched length \(L\) and force constant \(k\) is stretched by a small length \(x\). It is further stretched by another small length \(y\). Work done dwring the second stretching is
- A \(\frac{k y}{2}(x+2 y)\)
- B \(\frac{k}{2}(2 x+y)\)
- C ky \((x+2 y)\)
- D \(\frac{k y}{2}(2 x+y)\)
Answer & Solution
Correct Answer
(D) \(\frac{k y}{2}(2 x+y)\)
Step-by-step Solution
Detailed explanation
According to the question, In the first condition, \[ W_1=\frac{1}{2} k x^2 \] In the second condition, \[ W_2=\frac{1}{2} k(x+y)^2 \] Work for \(x\) to \(y\) expansion…
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