TS EAMCET · Physics · Motion In Two Dimensions
A body is projected from the ground at an angle of \(\tan ^{-1}(\sqrt{7})\) with the horizontal. At half of the maximum height, the speed of the body is ' \(n\) ' times the speed of projection. The value of ' \(n\) ' is
- A \(2\)
- B \(\frac{1}{2}\)
- C \(\frac{4}{3}\)
- D \(\frac{3}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{4}\)
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