TS EAMCET · Physics · Nuclear Physics
The radius of \({ }_{72} \mathrm{Te}^{125}\) nucleus is 6 fermi. The radius of \({ }_{13} \mathrm{Al}^{27}\) nucleus in meters is
- A \(3.6 \times 10^{-12} \mathrm{~m}\)
- B \(3.6 \times 10^{-15} \mathrm{~m}\)
- C \(7.2 \times 10^{-8} \mathrm{~m}\)
- D \(7.2 \times 10^{-15} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(3.6 \times 10^{-15} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The relation between radius \((R)\) and atomic number \((A)\) is \(\frac{R_1}{R_2}=\left(\frac{A_1}{A_2}\right)^{1 / 3}\) Given, \(R_1=6\) fermi, \(A_1=125, A_2=27\)…
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