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TS EAMCET · Physics · Waves and Sound

A diatomic gas of volume 2 m3 at pressure 2×105 N m-2 is compressed adiabatically to a volume 0.5 m3. The work done in this process is,
[Use 41.4=6.96]

  1. A 2.96×105 J
  2. B -2.96×105 J
  3. C -7.4×105 J
  4. D 7.4×105 J
Verified Solution

Answer & Solution

Correct Answer

(C) -7.4×105 J

Step-by-step Solution

Detailed explanation

In the adiabatic process, the formula of work done in terms of pressure and volume is, W=P1V1-P2V2γ-1 For diatomic gas the value of γ=1.4 Here P1=2×105 N m-2, V1=2 m3 and V2=0.5 m3 Put these values in the above formula, W=P1V1-P2V2γ-1 Here…
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