TS EAMCET · Physics · Electromagnetic Induction
An emf of 2.8 mV is induced in a rectangular loop of area \(150 \mathrm{~cm}^2\) when the current in the loop changes from 3 A to 8 A in a time of 0.2 s. Then the self-inductance of the loop is
- A \(112 \mu \mathrm{H}\)
- B \(56 \mu \mathrm{H}\)
- C \(28 \mu \mathrm{H}\)
- D \(84 \mu \mathrm{H}\)
Answer & Solution
Correct Answer
(A) \(112 \mu \mathrm{H}\)
Step-by-step Solution
Detailed explanation
\(L = \frac{\varepsilon \Delta t}{\Delta I}\) \(L = \frac{2.8 \times 10^{-3} \mathrm{~V} \times 0.2 \mathrm{~s}}{(8 \mathrm{~A} - 3 \mathrm{~A})}\) \(L = \frac{0.56 \times 10^{-3}}{5} \mathrm{~H} = 0.112 \times 10^{-3} \mathrm{~H} = 112 \mu \mathrm{H}\)
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