TS EAMCET · Physics · Work Power Energy
A body is moved along a straight line by an engine which delivers a constant power. The distance moved by the body in time ' \(\mathrm{t}\) ' is proportional to
- A \(\mathrm{t}^{1 / 2}\)
- B \(t^{3 / 4}\)
- C \(t^{3 / 2}\)
- D \(\mathrm{t}^2\)
Answer & Solution
Correct Answer
(C) \(t^{3 / 2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Power, } \mathrm{P}=\mathrm{Fv} \\ & =\frac{\mathrm{mas}}{\mathrm{t}} \quad\left(\because \mathrm{v}=\frac{\mathrm{s}}{\mathrm{t}}\right) \\ & \mathrm{P}=\frac{\mathrm{ms}^2}{\mathrm{t}^3} \because \mathrm{a}=\frac{\mathrm{s}}{\mathrm{t}^2}…
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