TS EAMCET · Physics · Ray Optics
1. The focal lengths of the objective and the eyepiece of a compound microscope are \(2 \mathrm{~cm}\) and \(3 \mathrm{~cm}\) respectively and the distance between them is \(15 \mathrm{~cm}\). The final image formed by the eyepiece is at infinity. The distances of the object and the image produced by the object from the objective lens are respectively
- A \(2.4 \mathrm{~cm}, 12 \mathrm{~cm}\)
- B \(2.4 \mathrm{~cm}, 15 \mathrm{~cm}\)
- C \(2.3 \mathrm{~cm}, 12 \mathrm{~cm}\)
- D \(2.3 \mathrm{~cm}, 3 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(2.4 \mathrm{~cm}, 12 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{f}_0=2 \mathrm{~cm}, \mathrm{f}_{\mathrm{e}}=3 \mathrm{~cm}\) and \(\mathrm{f}_0+\mathrm{f}_{\mathrm{e}}=15 \mathrm{~cm}\). Final image is formed at infinity, so object for eye-piece i.e., image formed by objective lens at \(\mathrm{f}=3 \mathrm{~cm}\) from it…
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