TS EAMCET · Physics · Current Electricity
If the resistances are chosen for the circuit shown in figure in such a way that no current flows through the battery with emf \(E_1\), the voltage \(V_2\) across \(R_2\) and the current \(Y_3\) flowing through \(R_3\) are respectively,

- A \(V_2=-4 V_1 l_3=\frac{5}{2} \mathrm{~A}\)
- B \(V_2=+4 V_1 f_3=\frac{5}{2} A\)
- C \(V_2=-3 V_1 f_3=1 \mathrm{~A}\)
- D \(V_2=+3 V_1 f_3=2 \mathrm{~A}\)
Answer & Solution
Correct Answer
(C) \(V_2=-3 V_1 f_3=1 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Resistance \(R_1\) and \(R_4\) are connected in series, so the circuit can be redrawn as As given, \(I_1=0 \mathrm{~A}\), so the potential drop of \(2 \mathrm{~V}\) takes place across the parallel branch \(\mathrm{AB}\) and resistor \(R_3\). Hence, \(2=I_3 R_3=I_3 2\)…
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