TS EAMCET · Physics · Waves and Sound
A sound wave of frequency \(\mathrm{v} \mathrm{Hz}\) initially travels a distance of \(1 \mathrm{~km}\) in air. Then, it gets reflected into a water reservoir of depth \(600 \mathrm{~m}\). The frequency of the wave at the bottom of the reservoir is \[ \text { ( } V_{\text {air }}=340 \mathrm{~m} / \mathrm{s} V_{\text {water }}=1484 \mathrm{~m} / \mathrm{s} \text { ) } \]
- A \(>v \mathrm{~Hz}\)
- B \( < v \mathrm{~Hz}\)
- C \(v \mathrm{~Hz}\)
- D 0 (the sound wave gets attenuated by water completely)
Answer & Solution
Correct Answer
(C) \(v \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
The frequency of sound wave remains constant
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