TS EAMCET · Physics · Thermal Properties of Matter
Consider two black bodies A and B having equal surface areas. On the surface of \(A\), ' \(n\) ' photons of frequency ' \(f\) ' are incident perpendicularly in a time ' \(t\) '. On the surface of \(B\), ' \(2 \mathrm{n}\) ' photons of frequency ' \(3 \mathrm{f}\) ' are incident perpendicularly in a time ' \(4 \mathrm{t}\) '. The ratio of average intensity of radiation on surface \(A\) to that on surface \(B\) is
- A \(2: 3\)
- B \(3: 2\)
- C \(1: 12\)
- D \(1: 24\)
Answer & Solution
Correct Answer
(A) \(2: 3\)
Step-by-step Solution
Detailed explanation
Intensity of radiation, \(I=\frac{E}{A t}\) For surface A, \[ \mathrm{I}_{\mathrm{A}}=\frac{\mathrm{nf}}{\mathrm{At}} \] For surface \(B\).…
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