TS EAMCET · Physics · Thermal Properties of Matter
A \(210 \mathrm{~W}\) heater is used to heat \(100 \mathrm{~g}\) water. The time required to raise the temperature of this water from \(25^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C}\) is (specific heat capacity of water \(=4200 \mathrm{~J} / \mathrm{Kg} \cdot{ }^{\circ} \mathrm{C}\) )
- A \(100 \mathrm{~s}\)
- B \(125 \mathrm{~s}\)
- C \(150 \mathrm{~s}\)
- D \(200 \mathrm{~s}\)
Answer & Solution
Correct Answer
(C) \(150 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Given, specific heat of water, \[ W=4200 \mathrm{~J} / \mathrm{Kg}^{\circ} \mathrm{C}=42 \times 10^3 \mathrm{~J} / \mathrm{Kg}^{\circ} \mathrm{C} \] change in temperature of water, \[ \Delta T=T_2-r_2=100-25=75^{\circ} \mathrm{C} \] mass of water,…
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