TS EAMCET · Physics · Motion In Two Dimensions
A body rotates about a stationary axis. If the angular deceleration is proportional to square root of angular speed, then the mean angular speed of the body, given \(\omega_0\) as the initial angular speed, is
- A \(\frac{\omega_0}{\sqrt{2}}\)
- B \(\frac{\omega_0}{4}\)
- C \(\frac{\omega_0}{2}\)
- D \(\frac{\omega_0}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{\omega_0}{3}\)
Step-by-step Solution
Detailed explanation
Given, angular deceleration \(\propto \sqrt{\text { angular speed }}\) i.e., \(\quad \frac{-d \omega}{d t} \propto \sqrt{\omega}\) or \(\quad \frac{-d \omega}{d t}=k \sqrt{\omega}\), where, \(k\) is constant or…
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