TS EAMCET · Physics · Semiconductors
In a transistor if \(\frac{I_C}{I_E}=\alpha\) and \(\frac{I_C}{I_B}=\beta\). If \(\alpha\) varies between \(\frac{20}{21}\) and \(\frac{100}{101}\), then the value of \(\beta\) lies between
- A \(1-10\)
- B \(0.95-0.99\)
- C \(20-100\)
- D \(200-300\)
Answer & Solution
Correct Answer
(C) \(20-100\)
Step-by-step Solution
Detailed explanation
\(\beta=\frac{\alpha}{1-\alpha}\) \(\beta_1=\frac{\frac{20}{21}}{1-\frac{20}{21}}=20, \quad \beta_2=\frac{\frac{100}{101}}{1-\frac{100}{101}}=100\) The value of \(\beta\) lies between \(20-100\).
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