TS EAMCET · Physics · Electrostatics
An infinite non-conducting sheet has a surface charge density \(2 \times 10^{-7} \mathrm{C} / \mathrm{m}^2\) on one side. The distance between two equipotential surfaces whose potential differ by \(90 \mathrm{~V}\) is (assume, \(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \frac{\mathrm{Nm}^2}{\mathrm{C}^2}\) )
- A \(20 \pi \mathrm{mm}\)
- B \(\frac{25}{\pi} \mathrm{mm}\)
- C \(\frac{12.5}{\pi} \mathrm{mm}\)
- D \(\frac{\pi}{20} \mathrm{~mm}\)
Answer & Solution
Correct Answer
(B) \(\frac{25}{\pi} \mathrm{mm}\)
Step-by-step Solution
Detailed explanation
Using \(\left|\frac{d \mathbf{V}}{d r}\right|=|\mathbf{E}|\), Distance between two equipotentials of a charged plate is…
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