TS EAMCET · Maths · Inverse Trigonometric Functions
The value of \(x\), where \(x>0\) and \(\tan \left(\sec ^{-1}\left(\frac{1}{x}\right)\right)=\sin \left(\tan ^{-1} 2\right)\) is
- A \(\sqrt{5}\)
- B \(\frac{\sqrt{5}}{3}\)
- C \(1\)
- D \(2 / 3\)
Answer & Solution
Correct Answer
(B) \(\frac{\sqrt{5}}{3}\)
Step-by-step Solution
Detailed explanation
Given, \(\tan \left(\sec ^{-1}\left(\frac{1}{x}\right)\right)=\sin \left(\tan ^{-1} 2\right)\)…
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