TS EAMCET · Maths · Circle
Two points from the set of concyclic points of the circle passing through \((1,1),(2,-1),(3,2)\) is
- A \(\left(\frac{5}{2}+\sqrt{\frac{5}{2}}, \frac{1}{2}+\sqrt{\frac{5}{2}}\right),\left(\frac{5}{2}, \frac{1}{2}+\sqrt{\frac{5}{2}}\right)\)
- B \(\left(\frac{5}{2}+\sqrt{\frac{5}{2}}, \frac{1}{2}\right),\left(\frac{5+\sqrt{5}}{2}, \frac{1+\sqrt{5}}{2}\right)\)
- C \(\left(\frac{5+\sqrt{5}}{2}, \frac{1+\sqrt{5}}{\sqrt{2}}\right) \cdot\left(\frac{5}{2}+\sqrt{\frac{5}{2}}+\frac{1+\sqrt{5}}{4}\right)\)
- D \(\left(\frac{5}{2}-\frac{\sqrt{5}}{2}, \frac{1}{2}-\frac{\sqrt{5}}{2}\right)\left(\frac{5}{2}-\frac{\sqrt{5}}{2}, \frac{1}{2}+\frac{\sqrt{5}}{2}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{5}{2}+\sqrt{\frac{5}{2}}, \frac{1}{2}\right),\left(\frac{5+\sqrt{5}}{2}, \frac{1+\sqrt{5}}{2}\right)\)
Step-by-step Solution
Detailed explanation
Equation of circle passing through the points \((1,1),(2,-1)\) and \((3,2)\) is \(\left|\begin{array}{cccc} x^2+y^2 & x & y & 1 \\ 1+1 & 1 & 1 & 1 \\ 4+1 & 2 & -1 & 1 \\ 9+4 & 3 & 2 & 1 \end{array}\right|=0\)…
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