TS EAMCET · Maths · Permutation Combination
The number of ways of arranging the letters of the word LINEAR so that the letters \(\mathrm{N}\) and \(\mathrm{R}\) do not come together and \(\mathrm{E}\) and \(\mathrm{A}\) come together is
- A 80
- B 60
- C 10
- D 144
Answer & Solution
Correct Answer
(D) 144
Step-by-step Solution
Detailed explanation
We have a word; LINEAR then no. of arrangements having EA together is \(5!\times 2=240\) ...(i) now an arrangement having RN and EA together is \(4!\times 2 \times 2=96\) ...(ii) Hence no. of words having \({N}\) and \({R}\) not together is \(240-96=144\)
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