TS EAMCET · Maths · Trigonometric Equations
If the possible solution of the equation \(2 \cos ^2 x+3 \sin x-3=0\) constitute two unequal angles of a triangle, then the third angle of that triangle is
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}\)
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