TS EAMCET · Physics · Wave Optics
When two light waves of equal intensity superimpose, the maximum intensity obtained is I. If the intensity of one of the waves is quadrupled, then the maximum intensity obtained is
- A \(\frac{4 \mathrm{I}}{9}\)
- B \(\frac{9 \mathrm{I}}{4}\)
- C \(\frac{2 \mathrm{I}}{3}\)
- D \(\frac{3 \mathrm{I}}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{9 \mathrm{I}}{4}\)
Step-by-step Solution
Detailed explanation
\(I = (\sqrt{I_0} + \sqrt{I_0})^2 = 4I_0\) \(I_{new} = (\sqrt{4I_0} + \sqrt{I_0})^2 = (2\sqrt{I_0} + \sqrt{I_0})^2 = (3\sqrt{I_0})^2 = 9I_0\) \(I_{new} = 9 \left(\frac{I}{4}\right) = \frac{9I}{4}\)
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