TS EAMCET · Maths · Application of Derivatives
The focal length of a mirror is given by \(\frac{2}{f}=\frac{1}{v}-\frac{1}{u}\). In finding the values of \(u\) and \(v\), the errors are equal to ' \(p\) '. Then, the relative error in \(f\) is
- A \(\frac{p}{2}\left(\frac{1}{u}+\frac{1}{v}\right)\)
- B \(p\left(\frac{1}{u}+\frac{1}{v}\right)\)
- C \(\frac{p}{2}\left(\frac{1}{u}-\frac{1}{v}\right)\)
- D \(p\left(\frac{1}{u}-\frac{1}{v}\right)\)
Answer & Solution
Correct Answer
(A) \(\frac{p}{2}\left(\frac{1}{u}+\frac{1}{v}\right)\)
Step-by-step Solution
Detailed explanation
Given, equation is \(\frac{2}{f}=\frac{1}{v}-\frac{1}{u}\) Differentiating the given equation, we have…
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